Programmer Guide/Command Reference/EVAL/vvset: Difference between revisions
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;Usage 1: '''<code>vvset(<var>x</var> , <var>y</var> {, <var>o</var> {, <var>d</var>, <var>n</var>}}})</code>''' | ;Usage 1: '''<code>vvset(<var>x</var> , <var>y</var> {, <var>o</var> {, <var>d</var>, <var>n</var>}}})</code>''' | ||
:;<var>x</var>: source vector | :;<var>x</var>: source vector | ||
:;<var>y</var>: replace value | :;<var>y</var>: replace value (scalar) | ||
:;<var>o</var>: starting index, 0 <= o < <code>nrow(''x'')</code> (default=0) | :;<var>o</var>: starting index, 0 <= o < <code>nrow(''x'')</code> (default=0) | ||
:;<var>d</var>: index increment (default=1) | :;<var>d</var>: index increment (default=1) |
Revision as of 07:58, 6 April 2011
Create a copy of the vector x and replace elements.
- Usage 1
vvset(x , y {, o {, d, n}}})
- x
- source vector
- y
- replace value (scalar)
- o
- starting index, 0 <= o <
nrow(x)
(default=0) - d
- index increment (default=1)
- n
- number of values to replace (default=
nrow(x)
)
- Result 1
- The result r is copy of the vector x. All elements r[o+i*d] (with: i = 0..n-1) are replaced by the value y.
- Usage 2
vvset(x , y {, o {, d}})
- x
- source vector
- y
- replace vector
- o
- starting index, 0 <= o <
nrow(x)
(default=0) - d
- index increment (default=1)
- Result 2
- The result r is copy of the vector x. All elements r[o+i*d] (with: i = 0..nrow(y)-1) are replaced by the value y[i].
The function failes if an index value is out of bounds.
Example:
#a := eval fill(10,0,1) #b := eval vvset($#a, -1, 1, 2, 5) // -> #b = { 0 , -1 , 2 , -1 , 4 , -1 , 6 , -1 , 8 , -1 } #c := eval vvset($#b, fill(4, 9, -3), 6, 1) // -> #c = { 0 , -1 , 2 , -1 , 4 , -1 , 9 , 6 , 3 , 0 }